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We know that for equilateral triangle,

$r_{1}=23 a andr_{2}=r_{3}=2a $

here, $a=6cm$

so , Total potential,

$V=r_{1}kq +r_{2}kq +r_{3}kq $

$v=kq(r_{1}1 +r_{2}1 +r_{3}1 )$

putting value of$k,q,r_{1},r_{2},r_{3}$ we get,

$V=9×10_{9}×5×10_{−6}×(3 ×0.031 +0.031 +0.031 )$

$V=15×10_{5}×(3 1 +2)$

solving we get

$V=3.866×10_{6}v$

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