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Question

Three charges q,Q,q are placed at equal distance on a straight line. If the total potential energy of the system is zero, then Q:q is:


  1. 1:4
  2. 1:4
  3. 1:2
  4. 2:1

A
1:2
B
2:1
C
1:4
D
1:4
Solution
Verified by Toppr

We know potential energy is a scalar quantity
Now total P.E. =k(q)(Q)x+k(q)(Q))x+k(q)(q)2x
given P.E. total =0
0=2kqQx+kq22x
0=4Q+q
Q:q=1:4

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