Three charges −q,Q,−q are placed at equal distance on a straight line. If the total potential energy of the system is zero, then Q:q is:
−1:4
1:4
1:2
2:1
A
1:2
B
2:1
C
1:4
D
−1:4
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Solution
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We know potential energy is a scalar quantity Now total P.E. =k(−q)(Q)x+k(−q)(Q))x+k(−q)(−q)2x
given P.E. total =0
0=−2kqQx+kq22x
0=−4Q+q Q:q=1:4
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