Three coins each 2 cm in diameter are placed touching one another- Find the area enclosed by them-

Question

Toppr Admin · Accepted Answer

Area required-area of -x25B3-ABC-x2212-3-xD7-area of 1 quadrant-x221A-34-xD7-2-2-x2212-3-xD7-60360-xD7-227-xD7-1-xD7-1-x221A-3-x2212-117-12-12-x2212-117-0-16-x33A0-

Three coins each 2 cm in diameter are placed touching one another. Find the area enclosed by them.

Area required=area of $△ A B C - 3 \times$ area of $1$ quadrant
$= \frac{\sqrt{3}}{4} \times {(2)}^{2} - 3 \times \frac{60}{360} \times \frac{22}{7} \times 1 \times 1$
$= \sqrt{3} - \frac{11}{7}$
$= \frac{12.12 - 11}{7} = 0.16 ㎠$

Three coins each 2 cm in diameter are placed touching one another. Find the area enclosed by them.

Area required=area of △ABC−3×area of 1 quadrant=√34×(2)2−3×60360×227×1×1=√3−117=12.12−117=0.16㎠

Area required=area of $△ A B C - 3 \times$ area of $1$ quadrant
$= \frac{\sqrt{3}}{4} \times {(2)}^{2} - 3 \times \frac{60}{360} \times \frac{22}{7} \times 1 \times 1$
$= \sqrt{3} - \frac{11}{7}$
$= \frac{12.12 - 11}{7} = 0.16 ㎠$