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Question

Three glass cylinders of equal height $$H = 30 cm$$ and same refractive index $$n = 1.5$$ are placed on a horizontal surface as shown in figure. Cylinder I has a flat top, cylinder II has a convex top and cylinder III has a concave top. The radii of curvature of the two curved tops are same (R = 3m ). If $$H_1, H_2$$ and $$H_3$$ are the apparent depths of a point X on the bottom of the three cylinders, respectively, the correct statement (s) is/are :

A
$$H_2 > H_1$$
B
$$H_3 > H_1$$
C
$$0.8 cm < (H_2 - H_1) < 0.9 \, cm$$
D
$$H_2 > H_3$$
Solution
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Correct option is D. $$H_2 > H_3$$
Case - I
$$H = 30 \, cm$$
$$n = 3/2$$
$$H_1 = H/n \Rightarrow \dfrac{30 \times 2}{3} = 20 \, cm$$
Case - II
$$R = 300 cm$$
$$\dfrac{n_2}{v} - \dfrac{n_1}{u} = \dfrac{n_2 - n_1}{R}$$
$$\dfrac{1}{-H_2} - \dfrac{3}{-2 \times 30} = \dfrac{1 - \dfrac{3}{2}}{-300}$$
$$H_2 = \dfrac{600}{29} = 20.684 cm$$
Case - III :
$$\dfrac{n_2}{v} - \dfrac{n_1}{u} = \dfrac{n_2 - n_1}{R} ; \dfrac{1}{H_3} - \dfrac{3}{-2 \times 30} = \dfrac{1 - \dfrac{3}{2}}{300}$$
$$; H_3 = \dfrac{600}{31} = 19.354 cm$$


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