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Question

Three resistances each of $3 Ω$ are connected as shown in figure. The resultant resistance between A and F is:

$9 Ω$
$2 Ω$
$4 Ω$
$1 Ω$

A

9 Ω

B

2 Ω

C

1 Ω

D

4 Ω

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Solution

Verified by Toppr

To draw the circuit bring point B to D and Point C to point E. From the diagram, inner two resistances are in parallel, and its equivalent is also parallel to the third resistance.
$∴ R_{A F} = \frac{\frac{R}{2} \times R}{\frac{3 R}{2}}$
$= \frac{R}{3}$
$\Rightarrow R_{A F} = 1 Ω$

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