Three sound waves of equal amplitudes have frequencies $(n - 1), n, (n + 1)$ . They superimpose to give beats. The number of beats produced per second will be

Question

Three sound waves of equal amplitudes have frequencies -n-1- n- -n-1- They superimpose to give beats- The number of beats produced per second will be2413

Toppr Admin · Accepted Answer

The formula for the beat frequency is fb-f2-x2212-f1Where f1 and f2 are the frequency of two waves-Nowfb-f2-x2212-f1fb-n-1-x2212-n-x2212-1-fb-n-1-x2212-n-1-fb-2Thus the number of beats produced per second will be 2-

Three sound waves of equal amplitudes have frequencies $(n - 1), n, (n + 1)$ . They superimpose to give beats. The number of beats produced per second will be
$2$
$4$
$1$
$3$

The formula for the beat frequency is $f_{b} = f_{2} - f_{1}$
Where $f_{1}$ and $f_{2}$ are the frequency of two waves.
Now

$f_{b} = f_{2} - f_{1}$

$f_{b} = (n + 1) - (n - 1)$

$f_{b} = (n + 1 - n + 1)$

$f_{b} = 2$

Thus the number of beats produced per second will be $2$ .

Three sound waves of equal amplitudes have frequencies (n−1),n,(n+1). They superimpose to give beats. The number of beats produced per second will be2413

The formula for the beat frequency is fb=f2−f1Where f1 and f2 are the frequency of two waves.Nowfb=f2−f1fb=(n+1)−(n−1)fb=(n+1−n+1)fb=2Thus the number of beats produced per second will be 2.

Three sound waves of equal amplitudes have frequencies $(n - 1), n, (n + 1)$ . They superimpose to give beats. The number of beats produced per second will be
$2$
$4$
$1$
$3$

The formula for the beat frequency is $f_{b} = f_{2} - f_{1}$
Where $f_{1}$ and $f_{2}$ are the frequency of two waves.
Now

$f_{b} = f_{2} - f_{1}$

$f_{b} = (n + 1) - (n - 1)$

$f_{b} = (n + 1 - n + 1)$

$f_{b} = 2$

Thus the number of beats produced per second will be $2$ .