Three tankers contain $$403$$ litres, $$434$$ litres and $$465$$ litres of diesel respectively. Find the maximum capacity of a container that can measure the diesel of the three containers exact number of times.
Maximum capacity of the required tanker$$=$$HCF of $$403, 434, 465$$
$$403=13\times 31$$
$$434=2\times 7\times 31$$
$$465=3\times 5\times 31$$
HCF$$=31$$.
$$\therefore$$ A container of capacity $$31$$ litres can measure the diesel of $$3$$ containers exact number of times.