To represent a rational number sqrt-2- on number line- take sides of right triangle as-

Question

Toppr Admin · Accepted Answer

Correct option is A- -1- and -1-Notice that -sqrt-2- -sqrt-1-2 - 1-2- So- we can form a length of -sqrt-2- units using two mutually perpendicular sides of length -1- unit each- -Since- -1-1-sqrt-2- form sides of a right angled triangle by Pythagoras theorem-

To represent a rational number $$\sqrt{2}$$ on number line, take sides of right triangle as:

Correct option is A. $$1$$ and $$1$$
Notice that $$\sqrt{2}= \sqrt{(1^2 + 1^2)}$$. So, we can form a length of $$\sqrt{2}$$ units using two mutually perpendicular sides of length $$1$$ unit each. (Since, $$1,1,\sqrt{2}$$ form sides of a right angled triangle by Pythagoras theorem).

To represent a rational number $$\sqrt{2}$$ on number line, take sides of right triangle as:

Correct option is A. $$1$$ and $$1$$Notice that $$\sqrt{2}= \sqrt{(1^2 + 1^2)}$$. So, we can form a length of $$\sqrt{2}$$ units using two mutually perpendicular sides of length $$1$$ unit each. (Since, $$1,1,\sqrt{2}$$ form sides of a right angled triangle by Pythagoras theorem).

Correct option is A. $$1$$ and $$1$$
Notice that $$\sqrt{2}= \sqrt{(1^2 + 1^2)}$$. So, we can form a length of $$\sqrt{2}$$ units using two mutually perpendicular sides of length $$1$$ unit each. (Since, $$1,1,\sqrt{2}$$ form sides of a right angled triangle by Pythagoras theorem).