0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Total number of $$6$$-digit number in which only and all the five digits $$1,3,5,7$$ and $$9$$ appear, is :

A
$$\dfrac{1}{2}(6!)$$
B
$$\dfrac{5}{2}(6!)$$
C
$$6!$$
D
$$5^6$$
Solution
Verified by Toppr

Correct option is C. $$\dfrac{5}{2}(6!)$$
$$1,3,5,7,9$$
$$\downarrow$$
selecting a digit which can be repeated $$=^5C_1$$
---------------------
Total number of $$6$$ digits $$=^5C_1\times \dfrac{6!}{2!}$$
$$=1800$$

Was this answer helpful?
22
Similar Questions
Q1
Total number of six-digit numbers in which only and all the five digits 1,3,5,7 and 9 appear, is

View Solution
Q2

Total number of six-digit numbers in which only and all the five digits 1,3,5,7 and 9 appear, is


View Solution
Q3
Total number of six-digit numbers in which all and only odd digits appear is
View Solution
Q4
Find the number of 6digit numbers in which all the odd digits and only odd digits will appear.
View Solution
Q5
The largest five-digit number that can be formed with the digits 2, 5, 9, 6, and 3 using each digit only once is .
View Solution