Twenty identical coins each with probability p of showing heads are tossed. If the probability of heads showing on 10 coins is same as that of tails showing on 11 coins, then p is

12

1021

1121

1321

A

1121

B

1321

C

12

D

1021

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Solution

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The probability of heads showing on 10coins =10p The probability of tails showing on 11 coins =11(1−p) according to question both are same => 10p=11(1−p) => p=1121

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