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Two balls are thrown with the same speed 10ms from the top of the cliff. The angles of their projection are 37° above and 37° below the horizontal as shown in the figure given below. How much farther along the ground does the above ball hit than the below ball? 10 ms *370 A 10 ms se answer: 20 m 12 m 9.6 m 4.8 m

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Q1
Two balls are thrown with the same speed $$10 ms^{-1}$$ from the top of the cliff. The angles of their projection are $$37^o$$ above and $$37^o$$ below the horizontal as shown in the figure given below. How much father along the ground does the above ball hit than the below ball?

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Q2

A ball is projected with a speed v0 at an angle of 37° with the horizontal, from the top of a cliff as shown in the figure. The ball has been thrown with the aim so that it just hits directly the edge of the cliff, but the ball just misses the target and falls on ground as shown in figure. [Take sin37°=35;cos37°=45;g=10ms-2.]

Based on above information, answer the following question:
The value of v0 is


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Q3

A ball is projected with a speed v0 at an angle of 37° with the horizontal, from the top of a cliff as shown in the figure. The ball has been thrown with the aim so that it just hits directly the edge of the cliff, but the ball just misses the target and falls on ground as shown in figure. [Take sin37°=35;cos37°=45;g=10ms-2.]

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Q4
A ball thrown down the incline strikes at a point on the incline 25 m below the horizontal as shown in the figure. If the ball rises to a maximum height of 20 m above the point of projection, the angle of projection α (with horizontal xaxis) is


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Q5

A ball A is projected from O with an initial velocity v0=7ms-1 in a direction 37° above the horizontal. Another ball B, 3m from O on a line 37° above the horizontal is released from rest at the instant A starts, as shown in figure.

[Take sin37°=37;cos37°=45;g=9.8ms-2]

Based on above information, answer the following question:

After how much time from the instant of projection of A, the two balls collide?


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