Two batteries- one of emf 18 volts and internal resistance 2Omega and the other of emf 12 volt and internal resistance 1Omega - are connected as shown-The voltmeter V will record a reading of-18 volt30 volt14 volt15 volt

Question

Two batteries- one of emf 18 volts and internal resistance 2Omega  and the other of emf 12 volt and internal resistance 1Omega - are connected as shown-The voltmeter V will record a reading of-18 volt30 volt14 volt15 volt

Toppr Admin · Accepted Answer

Since- the batteries are connected in parallel-V-E1r2-E2r1r1-r2V-18-xD7-1-12-xD7-21-2V-14Volt

Two batteries, one of emf 18 volts and internal resistance 2 $Ω$ and the other of emf 12 volt and internal resistance 1 $Ω$ , are connected as shown.The voltmeter V will record a reading of:

$18$ volt
$30$ volt
$14$ volt
$15$ volt

Since, the batteries are connected in parallel,
$V = \frac{E_{1} r_{2} + E_{2} r_{1}}{r_{1} + r_{2}}$

$V = \frac{18 \times 1 + 12 \times 2}{1 + 2}$

$V = 14 V o l t$

Two batteries, one of emf 18 volts and internal resistance 2Ω and the other of emf 12 volt and internal resistance 1Ω, are connected as shown.The voltmeter V will record a reading of:18 volt30 volt14 volt15 volt

Since, the batteries are connected in parallel,V=E1r2+E2r1r1+r2V=18×1+12×21+2V=14Volt

Two batteries, one of emf 18 volts and internal resistance 2 $Ω$ and the other of emf 12 volt and internal resistance 1 $Ω$ , are connected as shown.The voltmeter V will record a reading of:

$18$ volt
$30$ volt
$14$ volt
$15$ volt

Since, the batteries are connected in parallel,
$V = \frac{E_{1} r_{2} + E_{2} r_{1}}{r_{1} + r_{2}}$

$V = \frac{18 \times 1 + 12 \times 2}{1 + 2}$

$V = 14 V o l t$