Two bulbs A and B of equal capacity are filled with helium and $S O_{2}$ respectively at the same temperature, the pressure in the two bulbs is the same, what will be the ratio of the velocities of the molecules of two gases ? $(H e : S O_{2})$

Question

Two bulbs A and B of equal capacity are filled with helium and

S O_{2}

respectively at the same temperature, the pressure in the two bulbs is the same, what will be the ratio of the velocities of the molecules of two gases ?

(H e : S O_{2})

Toppr Admin · Accepted Answer

For He - urms-x221A-3RT-M-x221A-3RT-4-For SO2-urms-x221A-3RT-M-x221A-3RT-64-urmsofHeurmsofSO2-4

Two bulbs $A$ and $B$ of equal capacity are filled with $H e$ and $S O_{2}$ respectively at the same temperature. If the pressure in two the bulbs is same, what will be the ratio of $r m s$ speed of the molecules of two gases?

For $H e$ : $u_{r m s} = \sqrt{[(3 R T) / M]}$

$= \sqrt{[(3 R T) / 4]}$
For $S O_{2} : u_{r m s} = \sqrt{[(3 R T) / M]}$

$= \sqrt{[(3 R T) / 64]}$
$\frac{u_{r m s} o f H e}{u_{r m s} o f S O_{2}} = 4$

Two bulbs A and B of equal capacity are filled with He and SO2 respectively at the same temperature. If the pressure in two the bulbs is same, what will be the ratio of rms speed of the molecules of two gases?

For He : urms=√[(3RT)/M]=√[(3RT)/4]For SO2:urms=√[(3RT)/M]=√[(3RT)/64]urmsofHeurmsofSO2=4

Two bulbs $A$ and $B$ of equal capacity are filled with $H e$ and $S O_{2}$ respectively at the same temperature. If the pressure in two the bulbs is same, what will be the ratio of $r m s$ speed of the molecules of two gases?

For $H e$ : $u_{r m s} = \sqrt{[(3 R T) / M]}$

$= \sqrt{[(3 R T) / 4]}$
For $S O_{2} : u_{r m s} = \sqrt{[(3 R T) / M]}$

$= \sqrt{[(3 R T) / 64]}$
$\frac{u_{r m s} o f H e}{u_{r m s} o f S O_{2}} = 4$