Two capacitors of 0.5μF and 1μF are connected in parallel across a battery. If the charge on 0.5μF is 50μC, the charge on the other capacitor is :
100μC
50μC
25μC
Zero
A
100μC
B
50μC
C
25μC
D
Zero
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Solution
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V accross AB is constant Q1=C1V1forC=0.5μF Q2=C2V2forC=1μF Q1=50μC;C1=0.5μF⇒V1=100.V V1=V2=100V Q2=1μF×100V Q2=100μC Q=100μC
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