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Question

Two capacitors of 2 μF and 4 μF are connected in parallel. A third capacitor of 6 μF is connected in series. The combination is connected across a 12 V battery. The voltage across 2 μF capacitor is:
  1. 2 V
  2. 6 V
  3. 1 V
  4. 8 V

A
2 V
B
8 V
C
1 V
D
6 V
Solution
Verified by Toppr

CP=2+4=6μF
1C=16+16=26=13orC=3μF
Total charge
Q=CV=3×12=36μC
voltage across 6μF capacitor =36μC6μF=6V
Voltage across each of 2μF and 4μF capacitors
=12V6V
V=6V
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