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Correct options are A) , B) and D)

When the uncharged capacitor of capacity $1.5μF$ falls to the free end of the wire, it will make a closed loop circuit. Let $qμC$ charge flows in the closed loop in clockwise direction. Then final charges on different capacitors are as shown in figure.

Applying Kirchhoff's law for the loop,

$2300−q −1.5q +3360−q =0$

multiplying by 30 both sides, $4500−15q−20q+3600−10q=0$

or $8100=45q⇒q=180μC$

Thus, positive charge flow through A from left to right.

charge on $2μF$ becomes $=300−180=120μC$

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