Two cells are connected to a load resistor of resistance $$3.0\Omega$$. The electromotive force(e.m.f). and the internal resistance of each of the cells is shown. What is the current in the load resistor?

Question

Two cells are connected to a load resistor of resistance 3-0Omega- The electromotive force-e-m-f- and the internal resistance of each of the cells is shown- What is the current in the load resistor-

Toppr Admin · Accepted Answer

Correct option is C- -1-8-ALet the current be -I- A-Now - applying KVL in the circuit loop-anti clockwise-We have-160-1-2I -3 -0-8I-6 -3-0I-0-implies 5-0I - 9-implies I - -dfrac-9-5-0-implies I - 1-8 A-

Two cells are connected to a load resistor of resistance $$3.0\Omega$$. The electromotive force(e.m.f). and the internal resistance of each of the cells is shown. What is the current in the load resistor?

Correct option is C. $$1.8$$ALet the current be $$'I'\ A$$Now , applying KVL in the circuit loop.(anti clockwise)We have $$-1.2I +3 -0.8I+6 -3.0I=0$$$$\implies 5.0I = 9$$$$\implies I = \dfrac{9}{5.0}$$$$\implies I = 1.8 A$$

Correct option is C. $$1.8$$A
Let the current be $$'I'\ A$$
Now , applying KVL in the circuit loop.(anti clockwise)
We have
$$-1.2I +3 -0.8I+6 -3.0I=0$$
$$\implies 5.0I = 9$$
$$\implies I = \dfrac{9}{5.0}$$
$$\implies I = 1.8 A$$