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Question

- √r1r2
- r1−r2
- r1+r2
- r1+r22

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Solution

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Let the current flowing in the circuit be i.

Using Kirchhoff's voltage law:

⇒−E+ir1+iR−E+ir2=0

⇒i=2E(R+r1+r2)

Potential across first cell, VAB=ir1−E=2Er1(R+r1+r2)−E

For VAB=0, we get: 2Er1(R+r1+r2)−E=0

⇒ 2r1(R+r1+r2)=1

⇒2r1=R+r1+r2

⇒R=r1−r2

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