Question

# Two charges $$3\times 10^{-5}C$$ and $$5\times 10^{4}C$$ are placed at a distance $$10\ cm$$ form each other. Find the value of electrostatic force acting between them.

A
$$13.5\times 10^{11}N$$
B
$$40\times 10^{11}N$$
C
$$180\times 10^{9}N$$
D
$$13.5\times 10^{10}N$$
Solution
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#### Correct option is A. $$13.5\times 10^{11}N$$$$q_{1}=3\times 10^{-5}$$ $$q_{2}=5\times 10^{4}$$$$r=10\times 10^{-2}m$$$$F_{e}=\dfrac{1}{4\pi \varepsilon_{0}}\dfrac{q_{1}q_{2}}{r^{2}}$$$$\dfrac{9\times 10^{9}\times 3\times 10^{-5}\times 5\times 10^{4}}{(10\times 10^{-2})^{2}}$$$$\dfrac{9\times 15\times 10}{100\times 10^{-4}}$$$$\dfrac{135}{100}\times 10^{12}$$$$=1.35\times 10^{12}$$$$=13.5\times 10^{11}$$

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