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Two charges $$3\times 10^{-5}C$$ and $$5\times 10^{4}C$$ are placed at a distance $$10\ cm$$ form each other. Find the value of electrostatic force acting between them.

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Solution

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$$q_{1}=3\times 10^{-5}$$ $$q_{2}=5\times 10^{4}$$

$$r=10\times 10^{-2}m$$

$$F_{e}=\dfrac{1}{4\pi \varepsilon_{0}}\dfrac{q_{1}q_{2}}{r^{2}}$$

$$\dfrac{9\times 10^{9}\times 3\times 10^{-5}\times 5\times 10^{4}}{(10\times 10^{-2})^{2}}$$

$$\dfrac{9\times 15\times 10}{100\times 10^{-4}}$$

$$\dfrac{135}{100}\times 10^{12}$$

$$=1.35\times 10^{12}$$

$$=13.5\times 10^{11}$$

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