Two charges of 10mu C and -20mu C are separated by a distance of 20 cm- The distance of the point from smaller charge where electric potential is zero it lies between them is -dfrac-3-20-cm6-67 cm10 cm16 cm

Question

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Let x be the distance from 10-x3BC-c where potential is zero-x21D2-0-k-10-x3BC-C-x-k-x2212-20-x3BC-C-20-x2212-x-x21D2-0-10x-x2212-2020-x2212-x-x21D2-20-x2212-x-10-20x-x21D2-20-3x-xA0-x21D2-x-203-6-x22C5-67cm

Two charges of $10 μ C$ and $- 20 μ C$ are separated by a distance of $20 c m$ . The distance of the point from smaller charge where electric potential is zero if it lies between them is :

$\frac{3}{20} c m$
$6.67 c m$
$10 c m$
$16 c m$

Let x be the distance from $10 μ c$ where potential is zero
$\Rightarrow 0 = \frac{k (10 μ C)}{x} + \frac{k (- 20 μ C)}{20 - x}$

$\Rightarrow 0 = \frac{10}{x} - \frac{20}{20 - x}$

$\Rightarrow (20 - x) 10 = 20 x$
$\Rightarrow 20 = 3 x$

$\Rightarrow x = \frac{20}{3} = 6 \cdot 67 c m$

Two charges of 10μC and −20μC are separated by a distance of 20cm. The distance of the point from smaller charge where electric potential is zero if it lies between them is :320cm6.67cm10cm16cm

Let x be the distance from 10μc where potential is zero⇒0=k(10μC)x+k(−20μC)20−x⇒0=10x−2020−x⇒(20−x)10=20x⇒20=3x ⇒x=203=6⋅67cm

Two charges of $10 μ C$ and $- 20 μ C$ are separated by a distance of $20 c m$ . The distance of the point from smaller charge where electric potential is zero if it lies between them is :

$\frac{3}{20} c m$
$6.67 c m$
$10 c m$
$16 c m$

Let x be the distance from $10 μ c$ where potential is zero
$\Rightarrow 0 = \frac{k (10 μ C)}{x} + \frac{k (- 20 μ C)}{20 - x}$

$\Rightarrow 0 = \frac{10}{x} - \frac{20}{20 - x}$

$\Rightarrow (20 - x) 10 = 20 x$
$\Rightarrow 20 = 3 x$

$\Rightarrow x = \frac{20}{3} = 6 \cdot 67 c m$