Two charges -Q and -2Q are placed - -a-0- - -a-0- The locus of points in the plane of the charges where the potential is zero will be -straight linecircleparabolaellipse

Question

Toppr Admin · Accepted Answer

Let -x-y- be the point where potential due to the two charges is zero-Therefore-kQ-x221A-x-a-2-y2-x2212-2kQ-x221A-x-x2212-a-2-y2-0-x-x2212-a-2-y2-4-x-a-2-y2-x21D2-3x2-3y2-10xa-3a2-0The locus is thus a circle-

Two charges +Q and -2Q are placed at ( -a,0) & (+a,0). The locus of points in the plane of the charges where the potential is zero will be :
straight line
circle
parabola
ellipse

Let (x,y) be the point where potential due to the two charges is zero.
Therefore,
$k Q / \sqrt{(x + a)^{2} + y^{2}} - 2 k Q / \sqrt{(x - a)^{2} + y^{2}} = 0$
$(x - a)^{2} + y^{2} = 4 ((x + a)^{2} + y^{2}) \Rightarrow 3 x^{2} + 3 y^{2} + 10 x a + 3 a^{2} = 0$
The locus is thus a circle.

Two charges +Q and -2Q are placed at ( -a,0) & (+a,0). The locus of points in the plane of the charges where the potential is zero will be :straight linecircleparabolaellipse

Let (x,y) be the point where potential due to the two charges is zero.Therefore,kQ/√(x+a)2+y2−2kQ/√(x−a)2+y2=0(x−a)2+y2=4((x+a)2+y2)⇒3x2+3y2+10xa+3a2=0The locus is thus a circle.

Two charges +Q and -2Q are placed at ( -a,0) & (+a,0). The locus of points in the plane of the charges where the potential is zero will be :
straight line
circle
parabola
ellipse

Let (x,y) be the point where potential due to the two charges is zero.
Therefore,
$k Q / \sqrt{(x + a)^{2} + y^{2}} - 2 k Q / \sqrt{(x - a)^{2} + y^{2}} = 0$
$(x - a)^{2} + y^{2} = 4 ((x + a)^{2} + y^{2}) \Rightarrow 3 x^{2} + 3 y^{2} + 10 x a + 3 a^{2} = 0$
The locus is thus a circle.