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Question

Two charges 5μC and +10μC are placed 20 cm apart. The net electric field at the mid-point between the two charge is
  1. 4.5×105N/C directed towards +10μC
  2. 13.5×105N/C directed towards 5μC
  3. 13.5×105N/C directed towards +10μC
  4. 4.5×105N/C directed towards 5μC

A
4.5×105N/C directed towards +10μC
B
13.5×105N/C directed towards +10μC
C
4.5×105N/C directed towards 5μC
D
13.5×105N/C directed towards 5μC
Solution
Verified by Toppr

R.E.F image
¯Enet=¯E1+¯E2
=K(5×106)10×102+K(10×106)10×102
9×109[5×105+10×105]
135×104 N\C
¯Enet 13.5× 105 N/C towards 5μc

1239057_1301998_ans_1f25bf9339cb4b80a559f188ce788825.png

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