Two chords AB and AC of a circle with centre O are on the opposite sides of OA. Then:
∠OAB=∠OAC.
∠OAB≠∠OAC.
Cannot be determined
None of the above
A
Cannot be determined
B
None of the above
C
∠OAB=∠OAC.
D
∠OAB≠∠OAC.
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Solution
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Given-
AB & AC are chords of a circle with centre O.
They are to the opposite sides of OA.
To find out-
If ∠OAB=∠OAC.
Solution-
OB & OC are joined.
Between ΔAOC & ΔAOB we have,
OB=OC .....(radii of the same circle).
But it is not sure whether AB=AC or not.
So, we cannot have SSS test for the congruency of the triangles.
∴∠OAB≠∠OAC.
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