Two coherent monochromatic light beams of intensities I and 4I are superposed. The maximum and minimum possible resulting intensities are :

5I and 0

5I and 3I

9I and I

9I and 3I

A

9I and 3I

B

5I and 0

C

5I and 3I

D

9I and I

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Solution

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Maximum intensity, Imax=(√I1+√I2)2 =(√I+√4I)2 =9I Minimum intensity Imin=(√I1−√I2)2 (√I−√4I)2 =I

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