$$\textbf{Step 1: Find probability by taking ratio of favorable outcomes to the total outcomes}$$
$$\text{Let E}_{1} = \text{event of getting two heads}$$
$$\text{E}_{2} = \text{event of getting one head}$$
$$\text{E}_{3} = \text{event of getting no head}$$
$$P\text{(Two heads)}=P(E_1 ) $$
$$\Rightarrow P\text{(Two heads)}= \dfrac{105}{500} $$$$\quad \quad \quad \left[\because\boldsymbol{P(E)=\dfrac{\textbf{Favorable outcomes}}{\textbf{Total outcomes}}}\right]$$
$$\Rightarrow P\text{(Two heads)}= 0.21$$
$$P\text{(Two heads)}=P(E_2 ) $$
$$\Rightarrow P\text{(One heads)}= \dfrac{275}{500} $$$$\quad \quad \quad \left[\because\boldsymbol{P(E)=\dfrac{\textbf{Favorable outcomes}}{\textbf{Total outcomes}}}\right]$$
$$\Rightarrow P\text{(Two heads)}= 0.55$$
$$P\text{(Two heads)}=P(E_3) $$
$$\Rightarrow P\text{(No heads)}= \dfrac{120}{500} $$$$\quad \quad \quad \left[\because\boldsymbol{P(E)=\dfrac{\textbf{Favorable outcomes}}{\textbf{Total outcomes}}}\right]$$
$$\Rightarrow P\text{(No heads)}= 0.24$$
$$\textbf{Hence, probabilities for 2 heads, 1 head, and no heads are 0.21, 0.33 and 0.24 respectively}$$