Question

Two condenser of $2\mu F$ and $4\mu F$ are connected in series. The $p.d$ of $1200$ volt. The $p.d$ across $2\mu F$ is -

• A. $400V$
• B. $600V$
• C. $800V$
• D. $900V$

Answer 1

Answer: (C)

REF.Image

Q=CV

For a constant charge , $V\propto \frac{1}{C}$

$V_A\propto \frac{1}{C_A}$ & $V_B\propto \frac{1}{C_B}$

$V_A=\frac{CB}{CA+CB}\times V$

$V_A=\left(\frac{4}{2+4}\right)\times 1200$

$=\frac{4}{6}\times 1200$

= 800 V