Two condensers of capacities $10 μ F$ and $20 μ F$ have potential differences of 20V and 10V respectively. The total charge is

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Answer 1

$10 μ F$ $20 μ F$
20v 10v
q = cv $q_{2} = 200 μ c$
$q_{1} = 200 μ c$

Answer 2

10 μ F

20 μ F

20v 10v
q = cv

q_{2} = 200 μ c

q_{1} = 200 μ c

Two condensers of capacities $10 μ F$ and $20 μ F$ have potential differences of 20V and 10V respectively. The total charge is

$200 μ C$

$600 μ C$

$400 μ C$

Zero

Solution

$10 μ F$ $20 μ F$
20v 10v
q = cv $q_{2} = 200 μ c$
$q_{1} = 200 μ c$

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Similar questions

‘A’ and ‘B’ are two condensers of capacities 2 $μ F$ and 4 $μ F$ They are charged to potential differences of 12V and 6V respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is :

In the figure, given $C_{1} = 3 μ F, C_{2} = 5 μ F, C_{3} = 9 μ F$ and $C_{4} = 13 μ F$ . What is the potential difference between points $A$ and $B$ ?

Condensers of capacities 2 $μ$ F and 3 $μ$ F are connected in series and a condenser of capacity 1 $μ$ F is connected in parallel with them. The resultant capacity is :

Two capacitors of capacities 3 $μ$ F and 6 $μ F$ are connected in series and connected to 120V. The potential differences across 3 $μ$ F is $V_{0}$ and the charge here is $q_{0}$ . We have :
A) $q_{0} = 40 μ C$ B) $V_{0} = 60 V$
C) $V_{0} = 80 V$ D) $q_{0} = 240 μ C$

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Two condensers of capacities 10μF and 20μF have potential differences of 20V and 10V respectively. The total charge is

200μC

600μC

400μC

Zero

10μF 20μF 20v 10v q = cv q2​=200μc q1​=200μc

Patterns of problems

Was this answer helpful?

Similar questions

‘A’ and ‘B’ are two condensers of capacities 2 μF and 4μF They are charged to potential differences of 12V and 6V respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is :

In the figure, given C1​=3μ F,C2​=5μ F,C3​=9μ F and C4​=13μ F. What is the potential difference between points A and B ?

Condensers of capacities 2μF and 3μF are connected in series and a condenser of capacity 1μF is connected in parallel with them. The resultant capacity is :

Two capacitors of capacities 3μF and 6μF are connected in series and connected to 120V. The potential differences across 3μF is V0​ and the charge here is q0​. We have :A)q0​=40μC B) V0​=60VC)V0​=80V D)q0​=240μC

More From Chapter

Electrostatic Potential and Capacitance

Shortcuts & Tips

Mindmap

Diagram set

Memorization tricks

Common misconceptions

Problem solving tips

Cheatsheets

Practice more questions

8 Qs

3 Qs

3 Qs

3 Qs

1 Qs

57 Qs

Two condensers of capacities $10 μ F$ and $20 μ F$ have potential differences of 20V and 10V respectively. The total charge is

$200 μ C$

$600 μ C$

$400 μ C$

$10 μ F$ $20 μ F$
20v 10v
q = cv $q_{2} = 200 μ c$
$q_{1} = 200 μ c$

‘A’ and ‘B’ are two condensers of capacities 2 $μ F$ and 4 $μ F$ They are charged to potential differences of 12V and 6V respectively. If they are now connected (+ve to +ve), the charge that flows through the connecting wire is :

In the figure, given $C_{1} = 3 μ F, C_{2} = 5 μ F, C_{3} = 9 μ F$ and $C_{4} = 13 μ F$ . What is the potential difference between points $A$ and $B$ ?

Condensers of capacities 2 $μ$ F and 3 $μ$ F are connected in series and a condenser of capacity 1 $μ$ F is connected in parallel with them. The resultant capacity is :

Two capacitors of capacities 3 $μ$ F and 6 $μ F$ are connected in series and connected to 120V. The potential differences across 3 $μ$ F is $V_{0}$ and the charge here is $q_{0}$ . We have :
A) $q_{0} = 40 μ C$ B) $V_{0} = 60 V$
C) $V_{0} = 80 V$ D) $q_{0} = 240 μ C$