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Question

Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron =1.1 MeV and for helium =7.0 MeV)
  1. 30.2 MeV
  2. 23.6 MeV
  3. 25.8 MeV
  4. 32.4 MeV

A
23.6 MeV
B
25.8 MeV
C
32.4 MeV
D
30.2 MeV
Solution
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21H+21H42He+Energy

Mass of deuterium =2.013550

Mass of He =4.013490

The energy released in the process is :

ΔE=4.002602×7MeV2×2.01355×1.1MeV

ΔE=23.588MeV

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