Question

Open in App

Solution

Verified by Toppr

Let their velocities at 20cm a part

be v. Then

$ΔKE_{Total}=2[2Me v_{2}−2m (0)_{2}]=Mev_{2}$

Potential energy 10 cm (U Initial )

$=10010 −1ke_{2} =10ke_{2}$

Potential Energy 20 cm (U final )

$=20/100ke_{2} =5ke_{2}$

$ΔU_{Total}=U_{final}−U_{initial}$

$=5ke_{2}−10ke_{2}=−5ke_{2}$

As electrostatics force is

conservative,

$ΔKE_{Total}+ΔPE_{Total}=0$

$⇒mev_{2}−5ke_{2}=0$

$⇒v=me5ke_{2} =35.58m/s$

Solve any question of Electric Charges and Fields with:-

Was this answer helpful?

0

0