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Question

Two equal charges q of opposite sign are separated by a small distance '2l'. The electric potential at a point on the perpendicular bisector of the line joining the two charges at a distance r is :


  1. Zero
  2. 14πε02qr
  3. 14πε0qr
  4. 14πε02qr2

A
14πε02qr
B
Zero
C
14πε0qr
D
14πε02qr2
Solution
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V=K qr2 +l2+K(q)r2+l2

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