Two equal charges ‘q’ of opposite sign are separated by a small distance ‘d’. The electric intensity ‘E’ at a point on the straight line passing through the two charges at a very large distance ‘r’ from the midpoint of two charges is :
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Updated on : 2022-09-05
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Correct option is D)
As shown in the fig there are two electric fields E+q and E−q due to +q and −q charges respectively.
Resultant of this two oppositely directed electric fields gives the net electric field at that point.
∴ Electric field at that point is given by, E=E+q−E−q=Kq/(r−d/2)2−Kq/(r+d/2)2
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