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Updated on : 2022-09-05

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Correct option is C)

$μ_{2}=4/3Now densmaker formulaf1 =(μ_{r}−1)(R_{1}1 −R_{2}1 )for (1)f_{1}1 =(1.5−1)(R_{1}1 −(−R1 )) $$(equi convex lenSR_{1}=R_{2})$

$201 =21 ×R2 R=20cmfor (2)f_{2}1 =(34 −1)(R_{1}1 −R_{2}1 )f_{2}1 =31 (R−2 )f_{2}=−30cm $

$Now we know thatieffectivef_{eq}1 f_{eq}=15cm =P_{1}+P_{2}+P_{3}=201 −301 +201 So it is a converging lens of focal length15cm. $

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