Two forces each of magnitude 10 N act simultaneously on a body with their directions inclined to each other an angle of 120-0- and displaces the body over 10 m along the bisector of the angle between the two forces- Then the work done by each force is-5 J1 J100 J50 J

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Toppr Admin · Accepted Answer

Work done by each force -x222B-x2192-F-d-x2192-sF and s should be in the same direction so the component of F is taken

Two forces each of magnitude $10$ N act simultaneously on a body with their directions inclined to each other at an angle of $120^{0}$ and displaces the body over $10$ m along the bisector of the angle between the two forces. Then the work done by each force is:
5 J
1 J
100 J
50 J

Work done by each force $= \int \to F . d \to s$

F and s should be in the same direction so the component of F is taken

Two forces each of magnitude 10 N act simultaneously on a body with their directions inclined to each other at an angle of 1200 and displaces the body over 10 m along the bisector of the angle between the two forces. Then the work done by each force is:5 J1 J100 J50 J

Work done by each force =∫→F.d→sF and s should be in the same direction so the component of F is taken

Two forces each of magnitude $10$ N act simultaneously on a body with their directions inclined to each other at an angle of $120^{0}$ and displaces the body over $10$ m along the bisector of the angle between the two forces. Then the work done by each force is:
5 J
1 J
100 J
50 J

Work done by each force $= \int \to F . d \to s$

F and s should be in the same direction so the component of F is taken