0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Two gases A and B having molecular weight $$60$$ and $$45$$ respectively are enclosed in a vessel.The weight of A is $$0.5g$$ and that of $$B$$ is $$0.2g$$.The total pressure of the mixture is $$750mm$$.Calculate the partial pressure of the two gases.

Solution
Verified by Toppr

Was this answer helpful?
0
Similar Questions
Q1
Two gases A and B having molecular weights 60 and 40 respectively are enclosed in a vessel. The weight of A is 0.45 g and that of B is 0.1 g. The total pressure of the mixture is 900 mm of Hg. Calculate the partial pressure of the gas A.
View Solution
Q2
The pressure of a mixture of equal weights of two gases X and Y with molecular weight 4 and 40 respectively is 1.1 atm. The partial pressure of the gas X in the mixture is :
View Solution
Q3

A gaseous mixture of three gases A, B and C has a pressure of 10atm. The total number of moles of all gases is 10. The partial pressure of A and B are 3 and 1 atm respectively. If C has a molecular weight of 2, then find the weight of C in grams present in the mixture.


View Solution
Q4
10 moles of a mixture of gases has three gases A, B and C at a total pressure of 10 atm. The partial pressures of A and B are 3 atm and 1 atm respectively. If C has a molecular weight of 2g /mol, then the weight of C present in the mixture will be:
View Solution
Q5
The pressure of a mixture of equal weights of two gases of molecular weight 4 and 40 is 1.1 atm.What is the partial pressure of the lighter gas in the gas mixture?
View Solution