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The capacitor 1 has capacitance $C$ and as dielectric contains in capacitor 2 so its capacitance becomes $kC$.

The net capacitance $C_{eq}=C+kCC.kCβ=1+kCkβ$

and $Q_{eq}=C_{eq}E$

When dielectric is reemoved from capacitor 2, its capacitance becomes $C$.

now net capacitance $C_{eq}=C+CC.Cβ=2Cβ$

and $Q_{eq}=C_{eq}E=2CEβ$

When the capacitors are connected in series, they each have the same charge as the net capacitance. Thus, $Q_{eq}=Q_{1}=Q_{2}$ and $Q_{eq}=Q_{1}=Q_{2}$

$β΄Q_{1}Q_{1}β=Q_{2}Q_{2}β=k+12kβ$

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