0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Two identical capacitors are connected as shown in given figure, having a charge q0. A dielectric slab is introduced between the plates of the capacitor (I) so as to fill the gap, keeping the battery remain connected. The charge on each capacitors now will be :
146655.png
  1. 2q0[1+(1/k)]
  2. q0[1+(1/k)]
  3. 2q0(1+k)
  4. 2q0(1k)

A
q0[1+(1/k)]
B
2q0[1+(1/k)]
C
2q0(1k)
D
2q0(1+k)
Solution
Verified by Toppr

Without dielectric : Ceq=C0C0C0+C0=C02 and Qeq=C02×2V0=C0V0
As they are in series so the charge on each capacitors is equal to equivalent charge.i.e
Qeq=q0=C0V0
With dielectric in (I), the capacitance of it becomes kC0
now Ceq=kC0C0kC0+C0=kk+1C0 and
Qeq=kk+1C0(2V0)=2kk+1q0
Thus the on each capacitor is q=Qeq=2kk+1q0=2q01+1/k

Was this answer helpful?
2
Similar Questions
Q1
Two identical capacitors are connected as shown in given figure, having a charge q0. A dielectric slab is introduced between the plates of the capacitor (I) so as to fill the gap, keeping the battery remain connected. The charge on each capacitors now will be :
146655.png
View Solution
Q2

Two identical capacitors are connected as shown in the figure. A dielectric slab is introduced between the plates of one of the capacitors so as to fill the gap, the battery remaining connected. The charge on each capacitor will be :(charge on each condenser is q0; k = dielectric constant )


10615.png
View Solution
Q3

Two identical capacitors 1 and 2 are connected in series to a battery as shown in the figure. Capacitor 2 contains a dielectric slab of dielectric constant slab of dielectric constant K as shown. Q1 and Q2 are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are then:


View Solution
Q4
Two identical capacitors 1 and 2 connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant K as shown. If Q1 is the charge on each capacitor before removing the slab and Q2 is the charge on each capacitor after
moving the slab, then the correct relation between Q1 and Q2
is.

View Solution
Q5
Two identical capacitors 1 and 2 are connected in series to a battery as shown in figure. Capacitor 2 contains a dielectric slab of dielectric constant k as shown. Q1 and Q2 are the charges stored in the capacitors. Now the dielectric slab is removed and the corresponding charges are Q1 and Q2.
Then
126551.png
View Solution