Two identical particles are charged and held at a distance of 1m from each other. They are found to be attracting each other with a force of 0.027N. Now, they are connected by a conducting wire so that charge flows between them. When the charge flow stops, they are found to be repelling each other with a force of 0.009N. Find the initial charge on each particle :
None of these
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Correct option is A)
Let the initial charges are q1 and q2.
In first case , F=r2kq1q2=−0.027 (minus sign due to attraction force)
When a conducting wire are connected them, the charge on each particle will be half of the total charge i.e (q1+q2)/2.
For repulsion, F=12(9×109(2q1+q2)2=0.009
A) From q1q2=−3×10−12 and q1+q2=+2×10−6, we get after solving q1=3μC and q2=−1μC
B) From q1q2=−3×10−12 and q1+q2=−2×10−6, we get after solving q1=−3μC and q2=1μC
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