Two identical thin plano-convex glass lenses (refractive index 1.5) each having radius of curvature of 20cm are placed with their convex surfaces in contact at the centre. The intervening space is filled with oil of refractive index 1.7. The focal length of the combination is
A
50cm
B
−20cm
C
−25cm
D
−50cm
Hard
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Updated on : 2022-09-05
Solution
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Correct option is D)
Here the light passes through three refracting media, I, II & III as shown in the figure.
Media I & II has a refractive index 1.5 and radius of curvature 20cm. While medium II has a refractive index of 1.7 and it acts as a concave lens.
Let the focal length of the three media be f1,f2,f3.
Applying the lens makers formula
f1=(μ−1)(R11−R21)
For media I,
R1=∞ since it is a plano convex lens.
f11=(1.5−1)(∞1−−201)=0.5×201=401
For media II,
f21=(1.7−1)(−201−201)=0.7×(−202)=−100.7
For media III,
Since media I & III are similar we can write
f31=401
For applying the formula for equivalents lenses,
feq1=f11+f21+f31
⇒feq1=401−100.7+401
⇒feq1=401−2.8+1=−400.8=−501
∴feq=−50cm
Hence the correct answer is option (D).
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