Two magnetic poles have their strengths in the ratio 3 : 2. They are kept at a distance of 0.6 m in air and the force of repulsion is found to be 0.06 dynes. The pole strengths are (in amp. m)
1.8, 1.2
18, 12
0.6, 3.6
6, 4
A
6, 4
B
1.8, 1.2
C
18, 12
D
0.6, 3.6
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Solution
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1dyne=10−5
μ0=4π×10−7TmA−1
m1=3m
m2=3m
F=μ0m1×m24π×r2 r=0.6m
0.06×10−5=4π×10−7×3m×2m4π×(0.6)2
m2=(0.6)2
m=0.6
m1=1.8
m2=1.2
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