Two magnetic poles of strengths 40Am and 10Am are separated by a distance of 20cm in air. The force between them if the distance is reduced to 10cm is
4×10−3N,10−3N
10−3N,4×10−3N
2×10−3N,10−3N
10−3N,2×10−3N
A
4×10−3N,10−3N
B
10−3N,4×10−3N
C
2×10−3N,10−3N
D
10−3N,2×10−3N
Open in App
Solution
Verified by Toppr
m1=40Am,m2=10Am,d1=20cm d2=10cm F=μm1m24πd2 F1=10−7×40×10(20×10−2)2 =10−3 Force is inversely proportional to d2 F2=4×10−3
Was this answer helpful?
2
Similar Questions
Q1
Two point charges 3×10−6C and 8×10−6C repel each other by a force of 6×10−3N. If each of them is given an additional charge −6×106C, the force between them will be
View Solution
Q2
The velocity of water in a river is 18km/hr at the surface. If the river is 5m deep, find the shearing stress between the horizontal layers of water. The viscosity of water is 10−2Poise.
View Solution
Q3
1+4+10+19+...3n2−3n+22=
View Solution
Q4
A force of 50 dynes is acted on a body of mass 5 g which is at rest for an interval of 3 seconds, then impulseis
View Solution
Q5
Two magnetic poles of strengths 40Am and 10Am are separated by a distance of 20cm in air. The force between them if the distance is reduced to 10cm is