Solve
Guides
0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Standard XII
Physics
Newton's Laws for System of Particles
Question

Two masses m1 and m2 (m1>m2) are connected by massless flexible and inestensible string passed over massless and frictionless pulley. The acceleration of centre of mass is
  1. ⎧⎪ ⎪ ⎪⎩m1−m2m1+m2⎫⎪ ⎪ ⎪⎭2g
  2. m1−m2m1+m2g
  3. m1+m2m1−m2g
  4. Zero

A
m1−m2m1+m2g
B
⎧⎪ ⎪ ⎪⎩m1−m2m1+m2⎫⎪ ⎪ ⎪⎭2g
C
Zero
D
m1+m2m1−m2g
Open in App
Solution
Verified by Toppr


1473389_1207605_ans_4999b67faba5448ab9bbd2337136bf64.jpg

Was this answer helpful?
16
Similar Questions
Q1
Two masses m1 and m2 (m1>m2) are connected by massless flexible and inestensible string passed over massless and frictionless pulley. The acceleration of centre of mass is
View Solution
Q2
The two bodies of masses m1 and m2(m1>m2) respectively are tied to the ends of a string which passes over a light frictionless pulley. The masses are initially at rest and released. The acceleration of the centre of mass is
View Solution
Q3

Two bodies of masses m1 and m2 are connected by a light, inextensible string, which passes over a frictionless pulley. If the pulley is moving upward with uniform acceleration g, then the tension in the string is


View Solution
Q4
Two blocks of M1 and M2 (m1>m2) are connected by a massless string passing over a frictionless Pulley magnitude of acceleration of block would be. So acceleration would be (m1-m2/m1+m2)×g. So what will the acceleration of m1 which is smaller in wieght
View Solution
Q5

Two spheres of masses m1 and m2 (m1>m2) respectively are tied to the ends of a light, inextensible string which passes over a light frictionless pulley. When the masses are released from their initial state of rest, the acceleration of their centre of mass is:



View Solution