0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Two masses m1 and m2 (m1<m2) are released from rest from a finite distance. They start under their mutual gravitational attraction-
  1. Acceleration of m2 is more than that of m1
  2. Acceleration of m1 is more than that of m2.
  3. Centre of mass of system will remain at rest in all the reference frame
  4. Total energy of system remains constant

A
Acceleration of m1 is more than that of m2.
B
Total energy of system remains constant
C
Acceleration of m2 is more than that of m1
D
Centre of mass of system will remain at rest in all the reference frame
Solution
Verified by Toppr

Mutual force of attraction is same on two bodies, but acceleration a=Fm

Therefore, a1m

As m1<m2, a2<a1

Here, Potential energy is getting converted to kinetic energy.

Therefore, no energy loss.

Was this answer helpful?
0
Similar Questions
Q1

Two massesm1 and m2 (m1 < m2) are released from rest from a finite distance. They start under their mutual gravitational attraction-


View Solution
Q2
Two masses m1 and m2 (m1<m2) are released from rest from a finite distance. They start under their mutual gravitational attraction-
View Solution
Q3
Two masses m1 and m2 (m1<m2) are released from rest from a finite distance. They start to move under their mutual gravitational attraction. Identify the incorrect statement.
View Solution
Q4
Two masses m1 and m2 (m1 < m2) are released from rest from a finite distance between them. They start moving under the mutual gravitational attraction.
Which of the given options is correct?

View Solution
Q5

Two spheres of masses m1 and m2 (m1>m2) respectively are tied to the ends of a light, inextensible string which passes over a light frictionless pulley. When the masses are released from their initial state of rest, the acceleration of their centre of mass is:



View Solution