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Two men set out at the same time to walk towards each other from M and N, 72 km apart. The first man walks at the rate of 4 km/hr. The second man walks 2 km the first hour, 2 $\frac{1}{2}$ km the second hour, 3 km the third hour, and so on in arithmetic progression. Then the men will meet:
in 7 hours
in 8 $\frac{1}{4}$ hours
nearer M than N
nearer N than M
midway between M and N

A

nearer N than M

B

midway between M and N

C

in 7 hours

D

in 8

\frac{1}{4}

hours

E

nearer M than N

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