Two metal plates are separated by a distance d in a parallel plate condenser. A metal plate of thickness t and of the same area is inserted between the condenser plates. The value of capacitance increases by a factor of :
d−td
(t−td)
(2−td)
1(1−td)
A
(t−td)
B
d−td
C
1(1−td)
D
(2−td)
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Solution
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The capacitance after inserting dielectric slab of thickness t and dielectric constant K is: ϵ0Ad−t(1−1K)
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