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Solution

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Correct option is B)

Let the gap for capacitor 1 be x and that for capacitor 2 be y. Then,

$C_{1}=xϵ_{0}A $ and $C_{2}=yϵ_{0}A $

$x+y=d/2$

Since the two are in series,

$C_{′}=C_{1}+C_{2}C_{1}C_{2} =ϵ_{0}Ax1 +y1 xy1 $

$=x+yϵ_{0}A =d2ϵ_{0}A =2C$

Hence , $CC_{′} =2$

Hence , $CC_{′} =2$

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