Two numbers are in the ratio 5-6 - If the of the numbers is 132 - the two numbers-

Question

Toppr Admin · Accepted Answer

Let the ratio number be xSo- 1stno-5x2ndno-6xAccording to question-x21D2-6x-5x-132-x21D2-11x-132-x21D2-x-13211-12So- 1stno-5x-5-xD7-12-602ndno-6x-6-xD7-12-72

Two numbers are in the ratio $5 : 6$ . If the sum of the numbers is $132$ , find the two numbers.

Let the ratio number be $x$

So, $1 s t n o . = 5 x$

$2 n d n o . = 6 x$

According to question,

$\Rightarrow 6 x + 5 x = 132$

$\Rightarrow 11 x = 132$

$\Rightarrow x = \frac{132}{11} = 12$

So, $1 s t n o . = 5 x = 5 \times 12 = 60$

$2 n d n o . = 6 x = 6 \times 12 = 72$

Two numbers are in the ratio 5:6. If the sum of the numbers is 132 , find the two numbers.

Let the ratio number be xSo, 1stno.=5x2ndno.=6xAccording to question,⇒6x+5x=132⇒11x=132⇒x=13211=12So, 1stno.=5x=5×12=602ndno.=6x=6×12=72

Two numbers are in the ratio $5 : 6$ . If the sum of the numbers is $132$ , find the two numbers.

Let the ratio number be $x$

So, $1 s t n o . = 5 x$

$2 n d n o . = 6 x$

According to question,

$\Rightarrow 6 x + 5 x = 132$

$\Rightarrow 11 x = 132$

$\Rightarrow x = \frac{132}{11} = 12$

So, $1 s t n o . = 5 x = 5 \times 12 = 60$

$2 n d n o . = 6 x = 6 \times 12 = 72$