Two numbers are in the ratio 7-11- If 7 is added to each of the numbers- the ratio becomes 2-3- Find the numbers-

Question

Toppr Admin · Accepted Answer

Given -2- no-s are in the ratio -7-11-7- is added to these no-s then-160-the ratio -2-3-Let 1st no- -7x-2nd no- -11x-dfrac-7x-7-11x-7-dfrac-2-3-3-7x-7-2-11x-7-21x-21-22x-14-22x-21x-21-14-x-7-1st no -7-times 7-49-2nd no -11-times 7-77-

Two numbers are in the ratio $$7:11$$. If $$7$$ is added to each of the numbers, the ratio becomes $$2:3$$. Find the numbers.

Given $$'2'$$ no's are in the ratio $$7:11$$

$$'7'$$ is added to these no's then the ratio $$2:3$$

Let 1st no= $$7x$$

2nd no= $$11x$$

$$\dfrac{7x+7}{11x+7}=\dfrac{2}{3}$$

$$3(7x+7)=2(11x+7)$$

$$21x+21=22x+14$$

$$22x-21x=21-14$$

$$x=7$$

1st no $$=7\times 7=49$$

2nd no $$=11\times 7=77$$

Two numbers are in the ratio $$7:11$$. If $$7$$ is added to each of the numbers, the ratio becomes $$2:3$$. Find the numbers.

Given $$'2'$$ no's are in the ratio $$7:11$$$$'7'$$ is added to these no's then the ratio $$2:3$$Let 1st no= $$7x$$2nd no= $$11x$$$$\dfrac{7x+7}{11x+7}=\dfrac{2}{3}$$$$3(7x+7)=2(11x+7)$$$$21x+21=22x+14$$$$22x-21x=21-14$$$$x=7$$1st no $$=7\times 7=49$$2nd no $$=11\times 7=77$$

Given $$'2'$$ no's are in the ratio $$7:11$$

$$'7'$$ is added to these no's then the ratio $$2:3$$

Let 1st no= $$7x$$

2nd no= $$11x$$

$$\dfrac{7x+7}{11x+7}=\dfrac{2}{3}$$

$$3(7x+7)=2(11x+7)$$

$$21x+21=22x+14$$

$$22x-21x=21-14$$

$$x=7$$

1st no $$=7\times 7=49$$

2nd no $$=11\times 7=77$$