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Two parallel rays are incident on a thin lens of refractive index 1.5 as shown in figure and radius of curvature of its surfaces are 30 cm & 60 cm . Origin of coordinate axes is at the optical centre of the lens.Then
- focal length of lens is 120 cm
- y-coordinate of the point at which light rays focus is 4 πcm
- light rays get reflected (TIR) from first surface of the lens
- y-coordinate of the point at which light rays focus is -4 πcm
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Solution
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We use the lens maker's formula,
1f=(μ−1)(1R1−1R2)
μ=1.5,R1=−60,R2=−30
f=120
Since, a lens converges a parallel beam of light on its focus, the y coordinate of the lens is,
y=−fθ
y=120×6π180
Thus, y=−4π
μ=1.5,R1=−60,R2=−30
f=120
Since, a lens converges a parallel beam of light on its focus, the y coordinate of the lens is,
y=−fθ
y=120×6π180
Thus, y=−4π
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