0
You visited us 0 times! Enjoying our articles? Unlock Full Access!
Question

Two particles each of mass m and carrying charge Q are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces, then Q/m (in C/Kg) is of the order of:


  1. 105
  2. 1015
  3. 1010
  4. 1020

A
1015
B
105
C
1010
D
1020
Solution
Verified by Toppr

Given : Gravitational force = Electrostatics force
Let the distance between the rwo charges be r.
G(m)mr2=K Q .Qr2
GK=Q2m2
6.67×10119×109=Qm
Qm is the order of 1010

Was this answer helpful?
11
Similar Questions
Q1

Two particles each of mass m and carrying charge Q are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces, then Q/m (in C/Kg) is of the order of:


View Solution
Q2
Two identical particles each of mass M and charge Q are placed a certain distance part. If they are in equilibrium under mutual gravitational and electric force then calculate the order of QM in SI units.
View Solution
Q3
As shown in the adjoining figure two charged particles each having charge q and mass m are d distance apart from each other. If two particles are in equilibrium under the gravitational and electrostatic force, then the ratio qm (C/kg) is of the order

View Solution
Q4
Two identical metal sphere carrying charges of 9×109C and 3×109 C are brought in contact and then they are separated by a distance of 3 m and kept in a medium of dielectric constant 5. what is the electrostatic force between them ?
View Solution
Q5
The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance 5×1011m, will be (Charge on electron =1.6×1019C, mass of electron =9.1×1031 kg, mass of proton =1.6×1027kg,G=6.7×1011Nm2/kg2)


View Solution