Two particles each of mass $m$ and carrying charge $Q$ are separated by some distance. If they are in equilibrium under mutual gravitational and electrostatic forces, then Q/m (in C/Kg) is of the order of:

Question

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Answer 1

Given : Gravitational force = Electrostatics force
Let the distance between the rwo charges be $r$ .
$\Rightarrow \frac{G ( m ) m}{r ^{2}} = \frac{K Q . Q}{r ^{2}}$
$\Rightarrow \frac{G}{K} = \frac{Q ^{2}}{m ^{2}}$
$\Rightarrow \frac{6 . 6 7 \times 1 0 ^{- 11}}{9 \times 1 0 ^{9}} = \frac{Q}{m}$
$∴ \frac{Q}{m}$ is the order of $1 0^{- 10}$

Answer 2

Given : Gravitational force = Electrostatics force

Let the distance between the rwo charges be

r

.

\Rightarrow \frac{G ( m ) m}{r ^{2}} = \frac{K Q . Q}{r ^{2}}

\Rightarrow \frac{G}{K} = \frac{Q ^{2}}{m ^{2}}

\Rightarrow \frac{6 . 6 7 \times 1 0 ^{- 11}}{9 \times 1 0 ^{9}} = \frac{Q}{m}

∴ \frac{Q}{m}

is the order of

1 0^{- 10}