Solve

Guides

0

You visited us 0 times! Enjoying our articles? Unlock Full Access!

Question

Two particles executing SHM of same amplitude of 20 cm with same period along the same line about same equation position. The maximum distance between the two is 20 cm. Their phase difference in radiant is equal to
$\frac{π}{3}$
$\frac{π}{2}$
$\frac{2 π}{3}$
$\frac{4 π}{5}$

A

\frac{π}{2}

B

\frac{2 π}{3}

C

\frac{π}{3}

D

\frac{4 π}{5}

Open in App

Solution

Verified by Toppr

Was this answer helpful?

0

Similar Questions

Q1

Two particles executing SHM of same amplitude of 20 cm with same period along the same line about same equation position. The maximum distance between the two is 20 cm. Their phase difference in radiant is equal to

View Solution

Q2

10. Two particles executing SHM of same amplitude of 20 cm with same period along the same line about same equilibrium position. The maximum distance between the two is 20 cm. Their phase difference in radian is equal to 2T 3) (4) 5

View Solution

Q3

Two particle executing SHM of same amplitude of 20 cm with same period along the same line about same equilibrium position. The maximum distance between the two is 20 cm. Their phase difference in radian is equal to

View Solution

Q4

Two particles execute SHM of same amplitude of

20 c m

with same period along the same line about the same equilibrium position. The maximum distance between the two is

20 c m

. Their phase difference in radians is

View Solution

Q5

Two particles execute SHM of same amplitude of 20 cm with same period along the same line about the same equilibrium position . The maximum distance between the two is 20 cm. Their phase difference in radius is

View Solution